Integrand size = 37, antiderivative size = 380 \[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\frac {2 \sqrt {2} b^2 \operatorname {EllipticPi}\left (-\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{(-a+b)^{3/2} (a+b)^{3/2} f g^{3/2} \sqrt {d \sin (e+f x)}}-\frac {2 \sqrt {2} b^2 \operatorname {EllipticPi}\left (\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{(-a+b)^{3/2} (a+b)^{3/2} f g^{3/2} \sqrt {d \sin (e+f x)}}+\frac {2 a \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d f g \sqrt {g \cos (e+f x)}}-\frac {2 b (d \sin (e+f x))^{3/2}}{\left (a^2-b^2\right ) d^2 f g \sqrt {g \cos (e+f x)}}+\frac {2 b \sqrt {g \cos (e+f x)} E\left (\left .e-\frac {\pi }{4}+f x\right |2\right ) \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d f g^2 \sqrt {\sin (2 e+2 f x)}} \]
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Time = 0.61 (sec) , antiderivative size = 380, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.270, Rules used = {2983, 2917, 2643, 2651, 2652, 2719, 2985, 2984, 504, 1232} \[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=-\frac {2 b (d \sin (e+f x))^{3/2}}{d^2 f g \left (a^2-b^2\right ) \sqrt {g \cos (e+f x)}}+\frac {2 b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f g^2 \left (a^2-b^2\right ) \sqrt {\sin (2 e+2 f x)}}+\frac {2 a \sqrt {d \sin (e+f x)}}{d f g \left (a^2-b^2\right ) \sqrt {g \cos (e+f x)}}+\frac {2 \sqrt {2} b^2 \sqrt {\sin (e+f x)} \operatorname {EllipticPi}\left (-\frac {\sqrt {b-a}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {\sin (e+f x)+1}}\right ),-1\right )}{f g^{3/2} (b-a)^{3/2} (a+b)^{3/2} \sqrt {d \sin (e+f x)}}-\frac {2 \sqrt {2} b^2 \sqrt {\sin (e+f x)} \operatorname {EllipticPi}\left (\frac {\sqrt {b-a}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {\sin (e+f x)+1}}\right ),-1\right )}{f g^{3/2} (b-a)^{3/2} (a+b)^{3/2} \sqrt {d \sin (e+f x)}} \]
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Rule 504
Rule 1232
Rule 2643
Rule 2651
Rule 2652
Rule 2719
Rule 2917
Rule 2983
Rule 2984
Rule 2985
Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {a-b \sin (e+f x)}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)}} \, dx}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx}{\left (a^2-b^2\right ) g^2} \\ & = \frac {a \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)}} \, dx}{a^2-b^2}-\frac {b \int \frac {\sqrt {d \sin (e+f x)}}{(g \cos (e+f x))^{3/2}} \, dx}{\left (a^2-b^2\right ) d}-\frac {\left (b^2 \sqrt {\sin (e+f x)}\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)} (a+b \sin (e+f x))} \, dx}{\left (a^2-b^2\right ) g^2 \sqrt {d \sin (e+f x)}} \\ & = \frac {2 a \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d f g \sqrt {g \cos (e+f x)}}-\frac {2 b (d \sin (e+f x))^{3/2}}{\left (a^2-b^2\right ) d^2 f g \sqrt {g \cos (e+f x)}}+\frac {(2 b) \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)} \, dx}{\left (a^2-b^2\right ) d g^2}+\frac {\left (4 \sqrt {2} b^2 \sqrt {\sin (e+f x)}\right ) \text {Subst}\left (\int \frac {x^2}{\left ((a+b) g^2+(a-b) x^4\right ) \sqrt {1-\frac {x^4}{g^2}}} \, dx,x,\frac {\sqrt {g \cos (e+f x)}}{\sqrt {1+\sin (e+f x)}}\right )}{\left (a^2-b^2\right ) f g \sqrt {d \sin (e+f x)}} \\ & = \frac {2 a \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d f g \sqrt {g \cos (e+f x)}}-\frac {2 b (d \sin (e+f x))^{3/2}}{\left (a^2-b^2\right ) d^2 f g \sqrt {g \cos (e+f x)}}+\frac {\left (2 \sqrt {2} b^2 \sqrt {\sin (e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {a+b} g-\sqrt {-a+b} x^2\right ) \sqrt {1-\frac {x^4}{g^2}}} \, dx,x,\frac {\sqrt {g \cos (e+f x)}}{\sqrt {1+\sin (e+f x)}}\right )}{\sqrt {-a+b} \left (a^2-b^2\right ) f g \sqrt {d \sin (e+f x)}}-\frac {\left (2 \sqrt {2} b^2 \sqrt {\sin (e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {a+b} g+\sqrt {-a+b} x^2\right ) \sqrt {1-\frac {x^4}{g^2}}} \, dx,x,\frac {\sqrt {g \cos (e+f x)}}{\sqrt {1+\sin (e+f x)}}\right )}{\sqrt {-a+b} \left (a^2-b^2\right ) f g \sqrt {d \sin (e+f x)}}+\frac {\left (2 b \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}\right ) \int \sqrt {\sin (2 e+2 f x)} \, dx}{\left (a^2-b^2\right ) d g^2 \sqrt {\sin (2 e+2 f x)}} \\ & = \frac {2 \sqrt {2} b^2 \operatorname {EllipticPi}\left (-\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{(-a+b)^{3/2} (a+b)^{3/2} f g^{3/2} \sqrt {d \sin (e+f x)}}-\frac {2 \sqrt {2} b^2 \operatorname {EllipticPi}\left (\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{(-a+b)^{3/2} (a+b)^{3/2} f g^{3/2} \sqrt {d \sin (e+f x)}}+\frac {2 a \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d f g \sqrt {g \cos (e+f x)}}-\frac {2 b (d \sin (e+f x))^{3/2}}{\left (a^2-b^2\right ) d^2 f g \sqrt {g \cos (e+f x)}}+\frac {2 b \sqrt {g \cos (e+f x)} E\left (\left .e-\frac {\pi }{4}+f x\right |2\right ) \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d f g^2 \sqrt {\sin (2 e+2 f x)}} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 22.13 (sec) , antiderivative size = 1279, normalized size of antiderivative = 3.37 \[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\frac {2 \cos (e+f x) \sin (e+f x) (a-b \sin (e+f x))}{\left (a^2-b^2\right ) f (g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)}}+\frac {b \cos ^{\frac {3}{2}}(e+f x) \sqrt {\sin (e+f x)} \left (\frac {4 a \left (-b \operatorname {AppellF1}\left (\frac {3}{4},-\frac {1}{4},1,\frac {7}{4},\cos ^2(e+f x),\frac {b^2 \cos ^2(e+f x)}{-a^2+b^2}\right )+a \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{4},1,\frac {7}{4},\cos ^2(e+f x),\frac {b^2 \cos ^2(e+f x)}{-a^2+b^2}\right )\right ) \cos ^{\frac {3}{2}}(e+f x) \left (a+b \sqrt {1-\cos ^2(e+f x)}\right ) \sin ^{\frac {3}{2}}(e+f x)}{3 \left (a^2-b^2\right ) \left (1-\cos ^2(e+f x)\right )^{3/4} (a+b \sin (e+f x))}+\frac {\cos (2 (e+f x)) \sqrt {\tan (e+f x)} \left (b \tan (e+f x)+a \sqrt {1+\tan ^2(e+f x)}\right ) \left (56 b \left (-3 a^2+b^2\right ) \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},-\tan ^2(e+f x),\left (-1+\frac {b^2}{a^2}\right ) \tan ^2(e+f x)\right ) \tan ^{\frac {3}{2}}(e+f x)+24 b \left (-a^2+b^2\right ) \operatorname {AppellF1}\left (\frac {7}{4},\frac {1}{2},1,\frac {11}{4},-\tan ^2(e+f x),\left (-1+\frac {b^2}{a^2}\right ) \tan ^2(e+f x)\right ) \tan ^{\frac {7}{2}}(e+f x)+21 a^{3/2} \left (4 \sqrt {2} a^{3/2} \arctan \left (1-\sqrt {2} \sqrt {\tan (e+f x)}\right )-4 \sqrt {2} a^{3/2} \arctan \left (1+\sqrt {2} \sqrt {\tan (e+f x)}\right )-\frac {4 \sqrt {2} a^2 \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}}{\sqrt {a}}\right )}{\sqrt [4]{a^2-b^2}}+\frac {2 \sqrt {2} b^2 \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}}{\sqrt {a}}\right )}{\sqrt [4]{a^2-b^2}}+\frac {4 \sqrt {2} a^2 \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}}{\sqrt {a}}\right )}{\sqrt [4]{a^2-b^2}}-\frac {2 \sqrt {2} b^2 \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}}{\sqrt {a}}\right )}{\sqrt [4]{a^2-b^2}}+2 \sqrt {2} a^{3/2} \log \left (1-\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right )-2 \sqrt {2} a^{3/2} \log \left (1+\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right )-\frac {2 \sqrt {2} a^2 \log \left (-a+\sqrt {2} \sqrt {a} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}-\sqrt {a^2-b^2} \tan (e+f x)\right )}{\sqrt [4]{a^2-b^2}}+\frac {\sqrt {2} b^2 \log \left (-a+\sqrt {2} \sqrt {a} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}-\sqrt {a^2-b^2} \tan (e+f x)\right )}{\sqrt [4]{a^2-b^2}}+\frac {2 \sqrt {2} a^2 \log \left (a+\sqrt {2} \sqrt {a} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}+\sqrt {a^2-b^2} \tan (e+f x)\right )}{\sqrt [4]{a^2-b^2}}-\frac {\sqrt {2} b^2 \log \left (a+\sqrt {2} \sqrt {a} \sqrt [4]{a^2-b^2} \sqrt {\tan (e+f x)}+\sqrt {a^2-b^2} \tan (e+f x)\right )}{\sqrt [4]{a^2-b^2}}+\frac {8 \sqrt {a} b \tan ^{\frac {3}{2}}(e+f x)}{\sqrt {1+\tan ^2(e+f x)}}\right )\right )}{84 a^2 b \cos ^{\frac {3}{2}}(e+f x) \sqrt {\sin (e+f x)} (a+b \sin (e+f x)) \left (-1+\tan ^2(e+f x)\right ) \sqrt {1+\tan ^2(e+f x)}}\right )}{(-a+b) (a+b) f (g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(1203\) vs. \(2(347)=694\).
Time = 2.31 (sec) , antiderivative size = 1204, normalized size of antiderivative = 3.17
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Timed out. \[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\text {Timed out} \]
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\[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int \frac {1}{\sqrt {d \sin {\left (e + f x \right )}} \left (g \cos {\left (e + f x \right )}\right )^{\frac {3}{2}} \left (a + b \sin {\left (e + f x \right )}\right )}\, dx \]
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\[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int { \frac {1}{\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (b \sin \left (f x + e\right ) + a\right )} \sqrt {d \sin \left (f x + e\right )}} \,d x } \]
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\[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int { \frac {1}{\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (b \sin \left (f x + e\right ) + a\right )} \sqrt {d \sin \left (f x + e\right )}} \,d x } \]
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Timed out. \[ \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int \frac {1}{{\left (g\,\cos \left (e+f\,x\right )\right )}^{3/2}\,\sqrt {d\,\sin \left (e+f\,x\right )}\,\left (a+b\,\sin \left (e+f\,x\right )\right )} \,d x \]
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